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Sequence and series calculator

Choose the type of sequence and what you know about it: the first term with the common difference or ratio, or any two terms. The calculator gives the nth term, the sum of the first n terms, the sum to infinity where it exists, and lists the terms.

The term to find, and how many terms to add.

Arithmetic sequence: term 10 39
a₁₀ (term 10)39
Sum of the first 10 terms S₁₀210
First term a3
Common difference d4
General termaₙ = 3 + (n − 1) × 4 = 4n − 1
First 10 terms3, 7, 11, 15, 19, 23, 27, 31, 35, 39
nTermRunning sum
133
2710
31121
41536
51955
62378
727105
831136
935171
1039210
01234567891011510152025303540 n term
Show the working, step by step
  1. Use the nth-term formula aₙ = a + (n − 1)d.

    a₁₀ = 3 + (10 − 1) × 4 = 3 + 36 = 39

  2. Sum of n terms: Sₙ = n/2 × (2a + (n − 1)d), which is n times the average of the first and last terms.

    S₁₀ = 10/2 × (2 × 3 + 9 × 4) = 5 × 42 = 210 Check: n × (first + last)/2 = 10 × (3 + 39)/2 = 210

An arithmetic series has no sum to infinity (unless every term is 0): its terms do not shrink towards 0.

The formulas

Sequencenth termSum of n termsSum to infinity
Arithmetica + (n − 1)dn/2 × (2a + (n − 1)d)none (unless all terms are 0)
Geometrica × rⁿ⁻¹a(1 − rⁿ)/(1 − r), r ≠ 1a/(1 − r), only if |r| < 1
Harmonic1 / (1/a + (n − 1)D)no closed formnone (it diverges)

A sequence is the list of terms; a series is their sum. In a geometric series with r = 1 every term equals a, and the sum is simply n × a.

A worked example

The default is the arithmetic sequence with a = 3, d = 4 and n = 10: 3, 7, 11, 15, …

  1. 10th term: a₁₀ = 3 + (10 − 1) × 4 = 3 + 36 = 39.
  2. Sum: S₁₀ = 10/2 × (2 × 3 + 9 × 4) = 5 × 42 = 210.
  3. Check: 10 × (3 + 39)/2 = 210, the count times the average of the first and last terms.
  4. General term: aₙ = 3 + 4(n − 1) = 4n − 1.

Switch to geometric with a = 3 and r = 1/2 and the 10th term is 3 × (1/2)⁹ = 3/512, the sum of ten terms is 3069/512 ≈ 5.994, and the sum to infinity is 3/(1 − 1/2) = 6. The partial sums creep up towards 6 without reaching it.

Where these come up

Arithmetic sequences model anything that changes by a fixed amount: seats per row in a theatre, a salary with a fixed yearly rise, simple interest. Geometric sequences model a fixed percentage change: compound interest, depreciation, population growth and the fading bounce of a ball. Harmonic sequences appear in music (string lengths giving overtones) and in averaging rates.

Common mistakes

  • Using n instead of n − 1. The first term has no difference added, so the 10th term adds 9 differences, not 10.
  • Using the sum to infinity when |r| ≥ 1. 1 + 2 + 4 + … has no finite sum; plugging r = 2 into a/(1 − r) gives a meaningless −1.
  • Ignoring the negative ratio. If two known terms are an even number of places apart, r and −r both fit. The calculator uses the positive one and reports the other.
  • Averaging a harmonic sequence's terms. Work with the reciprocals, which are arithmetic.

Common questions

How do I find the nth term of an arithmetic sequence?

aₙ = a + (n − 1)d, where a is the first term and d the common difference. For 3, 7, 11, … (a = 3, d = 4) the 10th term is 3 + 9 × 4 = 39, and the general term simplifies to aₙ = 4n − 1.

What is the sum of an arithmetic series?

Sₙ = n/2 × (2a + (n − 1)d), which is the number of terms times the average of the first and last terms. For the first 10 terms of 3, 7, 11, … that is 10 × (3 + 39)/2 = 210.

When does a geometric series have a sum to infinity?

Only when the common ratio satisfies |r| < 1, so the terms shrink towards zero. Then S∞ = a/(1 − r). For 3, 3/2, 3/4, … (r = 1/2), S∞ = 3/(1 − 1/2) = 6. With |r| ≥ 1 the terms do not shrink and the series has no finite sum.

How do I find a sequence from two of its terms?

For an arithmetic sequence the gap between terms p and q is (q − p) steps, so d = (a_q − a_p)/(q − p). For a geometric one, r^(q − p) = a_q/a_p. If the 3rd term is 12 and the 7th is 192, a geometric sequence has r⁴ = 16, so r = 2 (or −2) and the first term is 12 ÷ 2² = 3.

What is a harmonic sequence?

One whose reciprocals form an arithmetic sequence, such as 1/2, 1/5, 1/8, … (the reciprocals 2, 5, 8 go up by 3). Find the nth term by working with the reciprocals and flipping at the end: the 10th reciprocal is 2 + 9 × 3 = 29, so the 10th term is 1/29. There is no closed formula for the sum, so it is added term by term.