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Dorbish–Bowley price index calculator

The Dorbish–Bowley index splits the difference between Laspeyres and Paasche by taking their arithmetic mean. Enter each commodity's prices and quantities in the base and current years.

Prices and quantities
Commodityp₀ (base price)q₀ (base qty)p₁ (current price)q₁ (current qty)Remove

Add a row for each commodity. Prices must be above zero; quantities and weights cannot be negative.

P₀₁, Dorbish–Bowley price index 124.65
P₀₁ (Dorbish–Bowley)124.65
Change from the base+24.65%
Σp₀q₀770
Σp₁q₀970
Σp₀q₁750
Σp₁q₁925
Laspeyres (L)125.97
Paasche (P)123.33
Time reversal testP₀₁×P₁₀ = 1.0001 (not met)
Commodityp₀q₀p₁q₁p₀q₀p₁q₀p₀q₁p₁q₁
A10201515200300150225
B8151014120150112140
C530636150180180216
D2010249200240180216
E425432100100128128
Σ770970750925
Show the working, step by step
  1. Multiply across each row to get p₀q₀, p₁q₀, p₀q₁, p₁q₁, then add each column.

    Σp₀q₀ = 770 Σp₁q₀ = 970 Σp₀q₁ = 750 Σp₁q₁ = 925

  2. Laspeyres and Paasche indices:

    L = Σp₁q₀ / Σp₀q₀ × 100 = 970 / 770 × 100 = 125.97 P = Σp₁q₁ / Σp₀q₁ × 100 = 925 / 750 × 100 = 123.33

  3. Take their arithmetic mean.

    P₀₁ (Dorbish–Bowley) = (125.97 + 123.33) / 2 = 124.65

P₀₁ = 124.65 means prices in the current period are 24.65% higher than in the base period. Time reversal test: P₁₀ = 80.23, and P₀₁ × P₁₀ = 124.65/100 × 80.23/100 = 1.0001, which is not 1, so the test is not met.

The formula

P₀₁ = (L + P) / 2 L = Σp₁q₀ / Σp₀q₀ × 100 P = Σp₁q₁ / Σp₀q₁ × 100

Laspeyres uses the base-year basket and Paasche the current one. Neither is “right”: they answer slightly different questions and are biased in opposite directions. The Dorbish–Bowley index simply averages them.

A worked example

The calculator's default data, with the four product columns summed:

Commodityp₀q₀p₁q₁p₀q₀p₁q₀p₀q₁p₁q₁
A10201515200300150225
B8151014120150112140
C530636150180180216
D2010249200240180216
E425432100100128128
Σ770970750925
  1. Laspeyres: L = 970 / 770 × 100 = 125.97.
  2. Paasche: P = 925 / 750 × 100 = 123.33.
  3. Dorbish–Bowley: (125.97 + 123.33) / 2 = 124.65.

Kept to three decimals the answer is 124.654. Fisher's index on the same data is 124.647, so the two agree to two decimals, as they usually do when L and P are within a few points.

Does it over- or under-state inflation?

Laspeyres tends to overstate the rise in living costs (it keeps the old basket, heavy in goods that have since become dear) and Paasche tends to understate it (its basket has already shifted to goods that became cheap). Averaging the two removes most of both biases, so Dorbish–Bowley lands close to the true change. Because it is an arithmetic mean it sits slightly above Fisher, which gives it a very small upward lean compared with the ideal index. That lean only matters when L and P are far apart, for example over a long gap between base and current year.

How it compares

IndexFormulaDefault data
LaspeyresΣp₁q₀ / Σp₀q₀ × 100125.97
Marshall–EdgeworthΣp₁(q₀ + q₁) / Σp₀(q₀ + q₁) × 100124.67
Dorbish–Bowley(L + P) / 2124.65
Fisher√(L × P)124.65
PaascheΣp₁q₁ / Σp₀q₁ × 100123.33

Common mistakes

  • Rounding L and P heavily before averaging. Keep at least two decimals in each.
  • Confusing it with Marshall–Edgeworth, which averages the quantities, not the indices.

Common questions

What is the Dorbish–Bowley price index formula?

P₀₁ = (L + P) / 2 = ½ (Σp₁q₀/Σp₀q₀ + Σp₁q₁/Σp₀q₁) × 100: the simple arithmetic mean of the Laspeyres and Paasche indices. For the default data, (125.97 + 123.33) / 2 = 124.65.

What is the difference between Dorbish–Bowley and Fisher’s index?

Dorbish–Bowley takes the arithmetic mean of L and P; Fisher takes the geometric mean √(L × P). Because an arithmetic mean is never below a geometric mean, Dorbish–Bowley is always at least as large as Fisher. The gap is tiny when L and P are close: 124.654 against 124.647 on the default data, which both round to 124.65.

Does the Dorbish–Bowley index satisfy the time reversal test?

No, although it comes close when L and P are near each other. On the default data P₁₀ = 80.23 and P₀₁ × P₁₀ = 1.0001, not exactly 1. It fails the factor reversal test too (1.2014 against V₀₁ = 1.2013). Fisher's index passes both.

Is it spelled Dorbish, Drobisch or Bowley?

The formula is credited to the German mathematician Moritz Drobisch (1871) and to the British statistician Arthur Bowley. Indian textbooks usually write “Dorbish and Bowley”, and international texts “Drobisch”. They are the same index.

When should I use Dorbish–Bowley instead of Fisher?

When you only have a basic calculator: it needs no square root, and in practice it gives almost the same number. When a question asks for an index that passes the reversal tests, or asks for the “ideal” index, use Fisher.